cosA / 1 - sinA + cosA / 1 + sinA
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ACCORDING TO THE QUESTION:
COSA + COSA
1-SINA 1+SINA
TAKING LCM AND SOLVING
COSA(1+SINA) + COSA(1-SINA)
(1-SINA)(1+SINA)
COSA + COSASINA + COSA - COSASINA
1+SINA-SINA-SIN^2A
2COSA ................(AS, 1-SIN^2A=COS^2A)
1-SIN^2A
HENCE IT IS , 2COSA = 2 = 2SECA
COS^2A COSA
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