Question

(cosA/1-sinA)+(cosA/1+sinA)=4

Answer 1

I think 4 equal h too yeah answer h

Answer 2

Answer: $\sec A=2$

Consider L.H.S. $\frac{\cos A}{1-\sin A}+\frac{\cos A}{1+\sin A}$

Taking cos A as common outside ,we get

$\cos A(\frac{1}{1-\sin A}+\frac{1}{1+\sin A})\\\\=\cos A(\frac{1+\sin A+1-\sin A}{(1-\sin A)(1+\sin A)})\\\\=\cos A(\frac{2}{1-\sin^2 A})\\\\=\cos A(\frac{2}{\cos^2A})\\\\=\frac{2}{\cos A}=2\sec A$= Also, R.H.S.=4

Then, $2\sec A=4\\\\\Rightarrow\ \sec A=2$