Math, asked by balavarivasantpb0apm, 1 year ago

cosA/1-sinA+cosA/1+sinA

Answers

Answered by sharathkumar1
1
LHS
[cosA/(1-sinA)] + [cosA/(1+sinA)

Taking LCM
[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]
=(cosA+cotA + cosA - cotA)/(1-sin²A)
=2cosA/cos²A
=2/cosA
=2secA
RHS

balavarivasantpb0apm: had a great job thanks
sharathkumar1: with pleasure
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