Question

cosA/1+sinA=secA-tanA​

Answer 1

L.H.S ---

$cosA/1+sinA$

for (1-sinA)to multiply and divide-----

$cosA(1-sinA)÷(1-sin^2A)$

$cosA - cosA.sinA÷cos^2A$

$secA - tanA$.✏️✏️✏️✏️

L.H.S = R.H.S

Hence proved..

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Answer 2

L.H.S --

cosA/1+sinA

for (1-sinA)to multiple and divide---

$cosA(1-sinA)/cos^2A$

1-sinA/cosA

secA-tanA

please mark it brainlist answer.....✏️✏️✏️✏️