Question

cosA/1-sinA=secA+tanA

Answer 1

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{cc} \bf { \underline{ Solution \: }} \\ \\ \tt\green{ \frac{CosA}{1 - Sin A } = SecA + TanA} \\ \purple \ \: \\\tt \pink{ \frac{CosA}{1 - Sin A } } \\ \purple\: \: \: \: \: \\\tt \purple{ \frac{CosA}{1 - Sin A} \times \frac{1 +Sin A }{1 + Sin A} } \\ \purple\ \\\tt \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red{ \frac{CosA(1 + Sin A) }{1 - Sin {}^{2} A } } \\ \purple \ \\\tt \orange{ \frac{CosA(1 +Sin A ) }{Cos {}^{2} A} } \\ \purple\ \\ \tt \pink { \frac{1 + Sin A }{CosA} } \\ \\ \: \tt \red{Sec A + TanA} \\ \\ \: \tt \blue{Hope \: it's \: helps \: you }& \end{array}} \\ \end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered} \end{gathered} \end{gathered}$