Question

CosA÷1-SinA+SinA÷1-cosA+1=SinACosA ÷(1-SinA)(1-CosA)

Answer 1

Answer:

CosA/1-sinA + sinA/1-cosA +1=sinAcosA/(1-sinA)(1-cosA)

Solving LHS

=cosA(1-cosA) + sinA(1-sinA) + (1-sinA)(1-cosA//(1-sinA)(1-cosA)

=cosA-cos^2A + sinA-sin^2A+1-cosA-sinA+sinAcosA//(1-sinA)(1-cosA)

=cosA-cosA+sinA-sinA-(sin^2A+cos^2A)+1+sinAcosA/(1-sinA)(1-cosA)

=0+0-(1)+1+sinAcosA/(1-sinA)(1-cosA)

=sinAcosA/(1-sinA)(1-cosA)

Hence, LHS=RHS