Math, asked by prabath21, 11 months ago

cosa/1-sina+sina/1-cosa+1=sinacosa/(1-sina)(1-cosa)

Answers

Answered by poweruffgirls11228

cosa-cos²a+sina-sin²a/(1-sina)(1-cosa) +1

cosa+sina-1/(1-sina)(1-cosa) +1(1-sina)(1-cosa)

cosa+sina-1+(1-sina)(1-cosa)/(1-sina)(1-cosa)

cosa+sina-1+1-cos-sina+sina*cosa/(1-sina)(1-cosa)

sina*cosa/(1-sina)(1-cosa)

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Answered by srisuranamotorsfinan

Answer:

Step-by-step explanation:

Cosa/1-sina+sina/1-cosa+1=sinacosa/(1-sina)(1-cosa)

LHS

Cosa/1-sina+sina/1-cosa+1

Cosa(1-cosa)+sina(1-sina)+(1-sina)(1-cosa)/

(1-sina)(1-cosa)

Cosa-cos^2 a+sina-sin^2a+1-cosa-sina+sina.cosa/(1-sina)(1-cosa)

-(sin^2a+cos^2a)+1+sina.cosa/(1-sina)(1-cosa)

-1+1+sina.cosa/(1-sina)(1-cosa)

sina.cosa/(1-sina)(1-cosa)

LHS=RHS

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