Math, asked by morankhiraj, 5 months ago

cosA/1+sinA + tanA = secA​


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Answers

Answered by Anonymous
4

Hello!

Question:-

prove :-

\dfrac{CosA}{1+SinA}+TanA = Sec A

Proof :-

L.H.S =

\implies \dfrac{CosA}{1+SinA}+TanA

\implies \dfrac{CosA}{1+SinA}+\dfrac{sinA}{CosA}

\implies \dfrac{Cos²A+SinA(1+SinA)}{(1+SinA)CosA}

\implies \dfrac{Cos²A+SinA+Sin²A}{(1+SinA)CosA}

\implies \cancel\dfrac{1+SinA}{(1+SinA)CosA}

\implies \dfrac{1}{CosA} = SecA = R.H.S

since, L.H.S = R.H.S

hence verified

Answered by raghvendrark500
2

above one is correct solution

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