Question

cosA/1+sinA+tanA=secA​

Answer 1

Answer:

This is sum solution in photo.

Answer 2

Answer:

Step-by-step explanation:

Hey !!!

from LHS

cosA /1 + sinA + tana

CosA /1 + sinA × 1 - sinA /1 - sinA + tanA

[here , by ( 1 - sinA) multiplied on numerator and denominator cosA/1 + sinA ] or in simple way rasionalising process of (cosA/1 + sinA )

we get ,

cos ( 1 - sinA )

-------------------------- + tanA

( 1 + sinA ) ( 1 - sinA )

=> cos ( 1 - sinA )

----------------------- + tanA

cos²A

=> 1 - sinA / cosA + tanA

=> secA - tanA + tanA

=> secA RHS prooved here ✒

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Hope it helps you !!