Question

CosA(1+tan sqaure A)=secA

Answer 1

Answer:

⚠ _ Hello _ ⚠

Step-by-step explanation:

$by \: the \: property \\ { \sec(a) }^{2} = (1 + { \tan(a) }^{2} ) \\ \\ \cos(a) \: \times { \sec(a) }^{2} \\ \cos(a) \times \frac{1}{ { \cos(a) }^{2} } \\ = > \frac{1}{ \cos(a) } \\ \sec(a) = > \sec(a)$

Hope it's help u