cosA/1-TanA-Sin^2A/cosA-sinA=1+sinA/cosA
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Step-by-step explanation:
cosA/1-tanA-sin²A/cosA-sinA
=cosA/{1-(sinA/cosA)}-sin²A/(cosA-sinA)
=cosA/{(cosA-sinA)/cosA}-sin²A/(cosA-sinA)
=cos²A/(cosA-sinA)-sin²A/(cosA-sinA)
=(cos²A-sin²A)/(cosA-sinA)
=(cosA+sinA)(cosA-sinA)/(cosA-sinA)
=sinA+cosA (Proved)
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