Math, asked by cressidaleitao, 4 months ago

cosA/1-tanA - sin2A/cosA-sinA = cosA+ sinA

Answers

Answered by narendradhage86

0

Answer:

what is this

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Answered by XXitswourldqueenXX

1

Answer:

LHS=cosA1−tanA+sin2AsinA−cosA

=cosA1−sinAcosA+sin2AsinA−cosA

=cos2AcosA−sinA+sin2AsinA−cosA

=−cos2AsinA−cosA+sin2AsinA−cosA

=−cos2A+sin2AsinA−cosA

=sin2A−cos2AsinA−cosA

=(sinA+cosA)(sinA−cosA)sinA−cosA

=sinA+cosA

=RHS

navn4420: hi happy Republic Day

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