Question

cosA/1-tanA +sinA/1-cotA=cosA-sinA

Answer 1

Answer:

Step-by-step explanation:

LHS

=cosA/(1-tanA)+sinA/(1-cotA)

=cos A/(1 - sin A/cos A) + sin A/(1 - cos A/sin A)

=cos²A/ (cos A - sin A) + sin²A / (sin A - cos A)

=cos²A/ (cos A - sin A) - sin²A / (cos A - sin A)

=(cos ² A - sin ² A) / (cos A - sin A)

=(cos A - sin A)(cos A + sin A) / (cos A - sin A)

=cos A + sin A i.e RHS

Answer 2

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Refer to attachment..

$\huge{\underline{\underline{\mathfrak{Thank you}}}}$