Math, asked by anantha2t, 3 months ago

cosA/1/-tanA+sinA/1-cotA=sinA+cosA

Answers

Answered by poojadixit5711

0

=cosA/1-tanA+sinA/1-cotA

=cosA/1-sinA/cosA+sinA/1-cosA/sinA

=cos2A/cosA-sinA-sin2A/cosA-sinA

=cos2A-sin2A/cosA-sinA

=(cosA+sinA)(cosA-sinA)/cosA-sinA

=sinA+cosA.

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