Math, asked by meesaajay97, 2 months ago

cosA/1-tanA + sinA/1-cotA = sinA + cosA

Answers

Answered by s02371joshuaprince47

Answer:

Step-by-step explanation:

CosA1–SinA+SinA1−CotA=SinA+CosA

LHS = CosA1–SinA+SinA1−CotA LHS=CosA1−SinACosA+SinA1−CosASinA LHS=Cos2ACosA–SinA+Sin2ASinA–CosA LHS=Cos2A–Sin2ACosA–SinA LHS=(CosA+SinA)(CosA–SinA)CosA–SinA LHS=(CosA+SinA) = RHS

LHS = RHS

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cosA/1-tanA + sinA/1-cotA = sinA + cosA​

Answers

cosA/1-tanA + sinA/1-cotA = sinA + cosA