Math, asked by rosemarydsouza1718, 3 months ago

COSA =2/3? find Sec A , tana A ,2Sec^2A+2tans^2
A - 7

Answers

Answered by sirireddykristipati

0

Step-by-step explanation:

sec A = 1/cosA

= 1/(2/3)

= 3/2

tanA

sec^2A - tan^2A = 1

sec^2A - 1= tan^2A

(3/2)^2 - 1 = tan^2A

9/4 - 1 = tan^2A

5/4 = tan^2A

tanA = (root(5))/2

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