Question

cosA=2/5,find the value of 4+4 tan^A (^)this is root

Answer 1

cosA = 2/5 = b / h 

h^2 = b^2 + p^2
5^2 = 2^2 + p^2
25  = 4 + p^2
p^2 = 21
p = root 21
                         =  4 + 4 tan^2A
                         =  4 + 4 * p^2 / b^2
                         =  4 + 4 * 21 / 4
                         =  25

Answer 2

here your ans
sure you will get result

Given:-)
cos a=2/5
4+4 tan^2a=4(1+tan^2a)
4 sec^2a{1+tan^2a=sec^2a}
4/cos^2a{sec^2a=1/cos^2a}
4/(2/5)^2=4/4/25=4×25/4=25 ans.....

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