Question

CosA=3/4, SinA is equal to​

Answer 1

1. let ABC be a triangle
2. then by Pythagoras theorem
3. (AC) ^²=AB^²+BC^²
4. (4) ^²=3^²+BC^²
5. 16=9+BC^²
6. BC^²=16-9
7. BC^²=7
8. BC=√7
9. SinA=BC/AC
10. SinA=√7/4