Math, asked by pjashan635, 1 year ago

CosA=3/4 then find the value of sinA/2sin5A/2

Answers

Answered by sprao53413

0

Answer:

1/(2sinA/2sin5A/2)=1/2[cos2A - cos 3A)

=1/2[2cos^2 A - 1+3cosA - 4cos^3 A)

=1/2[9/8-1+9/4-27/16]

=1/2[18-16+36-27]/16=11/32

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