Question

cosA=4/5 then secA+cosecA​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

cosA =1/secA ,   secA =5/4 ,  cos^2A+SIN^2A =1 , sinA =√1-cos^2A , √1-16/25 =3/5  ,  sinA = 3/5 , then cosec A =5/3  ,  5/4+5/3 =35/12