Question

{cosA÷b(a^2-b^2)}÷{cosA÷b(a^2 b^2)}=(a^2-b^2)÷(a^2 b^2) prove that

Answer 1

Answer:

sinA+sinB)^2+(cosA+cosB)^2 = a^2+b^2. ... sin^2A+sin^2B+2sinA.sinB+cos^2A+cos^2B+2cosA.cosB=a^2+b^2. or .(sin^2A+cos^2A)+(sin^2B+cos^2B)+2(cosA