Question

cosA +cos^2A=0 then find sin^2A-sin^4A​

Answer 1

Answer:

$\cos(x) + \cos {}^{2} (x) = 0 \\ \cos(x) (1 + \cos(x) ) = 0 \\ \cos(x) = 0 \: \: or \: - 1 \\ x = \frac{\pi}{2} \: \: and \: \: \pi$

Now

$\sin( \frac{\pi}{2} ) = 1 \\ \\ so \\ \sin {}^{2} (x) - \sin {}^{4} (x) = 1 - 1 = 0$

or

$\sin(\pi) = 0 \\ \\ \sin {}^{2} (x) - \sin {}^{4} (x) = 0 - 0 = 0$

Answer 2

\text{The value of }\sin^2a+\sin^4a \text{ is 1}The value of sin

2

a+sin

4

a is 1

Given

\cos a +\cos^2a=1cosa+cos

2

a=1

we have to find the value of \sin^2a+\sin^4asin

2

a+sin

4

a

As, \sin^2a+\cos^2a=1sin

2

a+cos

2

a=1

Given \cos a+\cos^2a=1cosa+cos

2

a=1

⇒ \cos a=1-\cos^2a=\sin^2acosa=1−cos

2

a=sin

2

a

\sin^2a+\sin^4asin

2

a+sin

4

a

Put the value of sin^2asin

2

a

= \cos a+\cos^2acosa+cos

2

a

=11

Step-by-step explanation:

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