Question

Cosa cos 2a cos 2^2a ... cos 2^(n-1)a=sin 2^na/2^n sina

Answer 1

Multiply and divide the given equation with 2sinA

(2sinA cosA* cos2A*.....)/2sinA

now 2sinA cosA  = sin2A , Replacing it in the equation

(sin2A* cos2A* cos4A* cos8A.....)/2sinA

Multiply and divide by 2

(2 sin2A cos2A* cos4A* cos8A......)/4sinA

2 sin2A cos2A   = sin4A , Replacing it in the equation

Repeating this step n times  we get

cosA* cos2A* cos4A* cos8A ......  cos2(n-1)A =  sin 2nA / 2n sinA

Answer 2

Answer:

Thanks for the answer

Step-by-step explanation:

Karthiksharma