cosa cos(60-a)cos(60+a)=1/4cos3a
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Step-by-step explanation:
here ,
cos (60-A) cos (60+A) = cos^2(A)- sin^2 (60)
= cos ^2 (A) - 3/4
now ,
cos A cos (60-A) cos (60+A = cos A ( cos^2 (A) - 3/4)
\ = 1/4 ( 4 cos ^3 (a) - 3 cos A)
{since 4 cos ^3 (a) - 3 cos A = cos 3A }
= 1/4 ( cos 3A)
hence proved
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