Math, asked by rajanivaloth, 11 months ago

cosA×cosecA-sinA×secA/cosA+sinA​

Answers

Answered by sandy1816
1

Step-by-step explanation:

cosAcosecA-sinAsecA/sinA+cosA

={cosA/sinA-sinA/cosA}/sinA+cosA

=(cos²A-sin²A/sinAcosA)×1/sinA+cosA

={(cosA-sinA)(cosA+sinA)/sinAcosA} ×1/(sinA+cosA)

=cosA-sinA/sinAcosA

=1/sinA-1/cosA

=cosecA-secA

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