Math, asked by namanbagdiya, 10 months ago

CosA.cosecA-sinA.secA/cosA+sinA=cosecA-secA

Answers

Answered by sandy1816

5

Step-by-step explanation:

cosAcosecA-sinAsecA/cosA+sinA

=cotA-tanA/cosA+sinA

=cos²A-sin²A/sinAcosA(cosA+sinA)

=cosA-sinA/sinAcosA

=cosecA-cotA

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