Math, asked by josvin007, 11 months ago

cosA-sinA+1/cosA+sinA-1

Answers

Answered by sandy1816

1

Answer:

devide by sinA in each term

cotA-1+cosecA/cotA+1-cosecA

=(cotA+cosecA)-(cosec²A-cot²A)/ (cotA-cosecA+1)

=(cotA+cosecA)(1-cosecA+cosA)/ cotA-cosecA+1

=cotA+cosecA

=cosA+1/sinA

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