Math, asked by rishabh0610, 11 months ago

cosA - sinA +1/ cosA + sinA -1 = cosecA + cotA​

Answers

Answered by sandy1816
0

Step-by-step explanation:

=cotA-1+cosecA/cotA +1-cosecA (devide sin in both numerator & denominator)

={(cotA+cscA)-1}/{(cotA-cscA)+1}×(cotA-cscA)/(cotA-cscA)

=cot²A-csc²A-(cotA-cscA)/(cotA-cscA+1)(cotA-cscA)

=cot²A-(1+cot²A)-(cotA-cscA)/(cotA-cscA+1)(cotA-cscA)

=-(1+cotA-cscA)/(cotA-cscA+1)(cotA-cscA)

=-1/(cotA-cscA)

=-1/-(cscA-cotA)×(cscA+cotA)/(cscA+cotA)

=cscA+cotA/csc²A-cot²A

=cscA+cotA

=R.H.S

Attachments:
Similar questions