Math, asked by tushar69939, 11 months ago

cosA-sinA+1÷cosA+sinA-1=cosecA+cotA​

Answers

Answered by aditioraon637
3

Step-by-step explanation:

LHS = cosA-sinA+1/cosA+sinA-1

divide both numerator and the denominator by sinA.

=cotA-1+cosecA/cotA+1-cosecA

={cotA+cosecA-(cosec²A-cot²A)} / (cotA-cosecA+1)

={(cotA+cosecA)-(cosecA+cotA)(cosecA-cot)} / (cotA-cosecA+1)

=[(cotA+cosecA){1-(cosecA-cotA)}] / (cotA-cosecA+1)

=(cotA+cosecA)(1-cosecA+cotA) / (cotA-cosecA+1)

=cotA+cosecA

RHS

LHS=RHS

Answered by sandy1816
0

Answer:

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