Question

(cosA-sinA+1)/(cosA+sinA-1)=cosecA+cotA​

Answer 1

Answer:

cosA-sinA+1/cosA+sinA-1=cosecA+cotA

Step-by-step explanation:

sinA will cancel

+1,-1 will also cancel

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Answer 2

LHS = ( cos A- sin A + 1)/(cos A + sin A - 1)

Dividing numerator and denominator both by sinA

Then LHS Becomes

(cot A - 1 + cosec A)/(cot A + 1 -cosec A)

=(cosec A + cot A - 1)/(cotA - cosec A +1)

={cosecA+cotA-( Cosec²A - Cot²A )}/( cotA-cosecA+1)

={(cosecA+cotA)-(cosecA+cotA)(cosecA-cotA)}/ ( cotA-cosecA+1)

={(cosecA+cotA)(1-cosecA+cotA)}/( cotA-cosecA+1)

=(cosecA+cotA)(cotA-cosecA+1)/( cotA-cosecA+1)

=cosecA+cotA

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