Question

(CosA- sinA +1)/(CosA sinA-1)=cosecA+cotA
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Answer 1

Answer:

LHS=cosA+sinA−1cosA−sinA+1

dividing Nr and Dr by sinA we get,

=sinAcosA+sinAsinA−sinA1sinAcosA−sinAsinA+sinA1

=cotA+1−cosecAcotA−1+cosecA

=cotA+1−cosecAcotA+cosecA−(cosec2A−cot2A)

=cotA+1−cosecA(cotA+cosecA)(1−cosecA+cotA)

=cotA+cosecA=RHS

Answer 2

Answer:

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