Math, asked by gours1884, 1 year ago

CosA -SinA +1/CosA +SinA - 1 = CosecA + CotA


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Answered by Nitin2112
0

(cosA-sinA+1)/(cosA+sinA-1) = cosecA+cotA  

L. H. S =  

Diving by sinA in numerator, we get  

(cotA-1+cosecA)/(cotA+1-cosecA)  

cotA+cosecA-1 / (cotA-cosecA+1)  

cotA+cosecA-(cosec²A-cot²A)/(cotA-cosecA+1)  

cotA+cosecA-[(cosecA+cotA)(cosecA-cotA)] / (cotA-cosecA+1)  

cosecA+cotA [(1-cosecA +cotA)] /(cotA-cosecA+1)  

cosecA+cotA [(1-cosecA+cotA)] /(1-cosecA+cotA)

Hope its helps  <3

Plz mark it as brainliest -_-

Answered by CaptainSteverogers
0

Answer:

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