cosA+sinA =✓2cosA then proved that sin2A-cos2A=0
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Answer:
Given, cosA+sinA=
2
cosA
⇒sinA=
2
cosA−cosA
⇒sinA=(
2
−1)cosA
⇒
cosA
sinA
=
2
−1
⇒tanA=
2
−1
⇒
tanA
1
=
2
−1
1
⇒cotA=
2
−1
1
×
2
+1
2
+1
⇒cotA=
2
+1
⇒
sinA
cosA
=
2
+1
⇒cosA=sinA(
2
+1)
⇒cosA=
2
sinA+sinA
⇒cosA−sinA=
2
sinA
Step-by-step explanation:
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