cosa+sina=√2cosa then show that cosa-sina=√2sina
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Hi...☺
Here is your answer...✌
GIVEN THAT,
cosA + sinA = √2 cosA
Squaring both sides
We get,
cos²A + sin²A + 2sinA cosA = 2cos²A
1 + 2sinA cosA = 2(1-sin²A)
2sinA cosA = 2 - 2sin²A - 1
2sin²A = 1 - 2sinA cosA
=> 1 - 2sinA cosA = 2sin²A
cos²A + sin²A - 2sinAcosA = 2sin²A
(cosA - sinA)² = 2sin²A
cosA - sinA = √2 sinA
[PROVED]
Here is your answer...✌
GIVEN THAT,
cosA + sinA = √2 cosA
Squaring both sides
We get,
cos²A + sin²A + 2sinA cosA = 2cos²A
1 + 2sinA cosA = 2(1-sin²A)
2sinA cosA = 2 - 2sin²A - 1
2sin²A = 1 - 2sinA cosA
=> 1 - 2sinA cosA = 2sin²A
cos²A + sin²A - 2sinAcosA = 2sin²A
(cosA - sinA)² = 2sin²A
cosA - sinA = √2 sinA
[PROVED]
Answered by
2
Hallo friend here is ur answer
Hope it will help u
Hope it will help u
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please mark it as brainliest
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