Math, asked by slaxminarayan903, 1 month ago

cosA - sinA/cosA+sinA

Answers

Answered by dkchakrabarty01

0

Answer:

(cosA-sinA)(cosA-sinA)/{(cosA+sinA)(cosA-sinA)}

=(cosA-sinA)^2/(cos^2A-sin^2A)

=(cos^A+sin^2A-2cosA.sinA)/cos2A

=(1-sin2A)/cos2A

=sec2A-tan2A

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