Math, asked by jaiswalraju12, 5 months ago

(cosA + sinA/ cosA - sinA) - (cosA - sinA / cosA +sinA

Answers

Answered by beenadevisantha786

0

Answer:

sinA+cosA

+

sinA+cosA

sinA−cosA

=

(sinA−cosA)(sinA+cosA)

(sinA+cosA)

2

+

(sinA−cosA)(sinA+cosA)

(sinA−cosA)

2

=

sin

2

A−cos

2

A

sin

2

A+cos

2

A+2sinAcosA+sin

2

A+cos

2

A−2sinAcosA

=

sin

2

A−cos

2

A

2

=

sin

2

A−(1−sin

2

A)

2

=

2sin

2

A−1

2

=

2(1−cos

2

A)−1

2

=

1−2cos

2

A

2

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