(cosA + sinA/ cosA - sinA) - (cosA - sinA / cosA +sinA
Answers
Answered by
0
Answer:
sinA+cosA
+
sinA+cosA
sinA−cosA
=
(sinA−cosA)(sinA+cosA)
(sinA+cosA)
2
+
(sinA−cosA)(sinA+cosA)
(sinA−cosA)
2
=
sin
2
A−cos
2
A
sin
2
A+cos
2
A+2sinAcosA+sin
2
A+cos
2
A−2sinAcosA
=
sin
2
A−cos
2
A
2
=
sin
2
A−(1−sin
2
A)
2
=
2sin
2
A−1
2
=
2(1−cos
2
A)−1
2
=
1−2cos
2
A
2
Similar questions
Math,
3 months ago
CBSE BOARD X,
3 months ago
Math,
3 months ago
Math,
7 months ago
Political Science,
1 year ago
English,
1 year ago