Math, asked by dabajpuavartha, 1 year ago

(CosA+sinA)=root2cosA prove that (cosA-sinA) =root2sinA.

Answers

Answered by prajapatyk

Given that,
CosA+SinA=√2CosA

SinA=√2CosA-CosA

SinA=CosA(√2-1)

SinA=CosA(√2-1)×(√2+1)/(√2+1)

SinA=CosA(2-1)/(√2+1)

SinA=CosA/(√2+1)

SinA(√2+1)=CosA

√2SinA+SinA=CosA

√2SinA=CosA-SinA

CosA-SinA=√2SinA

Hence proved.

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