Question

cosAcotA/1-sinA = 1+codec A
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Answer 1

Answer:

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Step-by-step explanation:

i don't understand it

Answer 2

Answer:

Hope it helps yaar

Step-by-step explanation:

Cos A  Cot A / 1 - Sin A  

Cos A * (Cos A /  Sin A) / 1 - Sin A                 {As Cot A = Cos A / Sin A}

Cos^2 A / Sin A / 1 - Sin A  

1 - Sin^2 A / Sin A (1 - Sin A)

(1 - Sin A)(1 + Sin A) / Sin A (1 - Sin A)          {As  a^2 - b^2 = (a - b)(a + b)}

By cancelling (1- Sin A) from numerator and denominator, we get,

1 + Sin A/ Sin A

By separating the denominator, we get,

1 / Sin A + Sin A / Sin A

1 / Sin A + 1  

Cosec A + 1       {As 1 / Sin A = Cosec A}

 

or

1 + Cosec A = R.H.S.

Thanks !!