Math, asked by aditiaditi952p35j8b, 1 year ago

cosalpha/sinalpha=m,cosalpha/sinalpha=n,(m^2-n^2)sin^2alpha=?

Answers

Answered by Jash0809
1
(m^2-n^2)sin^2alpha=0. (since m=n=cos alpha/sin alpha)

aditiaditi952p35j8b: detail solution plz
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