Question

Cos@=1/2 find value of 2sec@/1+tan2@

Answer 1

cos@=1/2

but,

cos60=1/2

therefore,

@=60°

now,

(2sec60)/sec²60

as [tan²@+1=sec²@]

sec60=2

so,

(2×2)/2×2

=>1

hope it helps

:-)

Answer 2

Answer:

cos@=1/2

but,

cos60=1/2

therefore,

@=60°

now,

(2sec60)/sec²60

as [tan²@+1=sec²@]

sec60=2

so,

(2×2)/2×2

=>1