Question

Cos@=b/h=1/2 (given)
By pythagoras theorem

h2=P2+B2
(2)2=P2+(1)2
4=P2+1
3=p2
underoot3=p


☆ sin@=p/h=underoot3/2
☆tan@=p/b=underoot3/1
=underoot3
If sin theta + cos theta = 1/2 then find the value of tan theta

Answer 1

$\sf{\large Cosθ = \frac{b}{h} = \frac{1}{2}} \: \: \: \: \: \: \: \: \sf----{\green{Given}}$

By Pythagoras theorem,

$\dashrightarrow\sf{\large {H}^{2} = {P}^{2} + {B}^{2} }$

$\dashrightarrow\sf{\large (2) 2= {P}^{2} + {1}^{2} }$

$\dashrightarrow\sf{\large 4= {P}^{2} +1}$

$\dashrightarrow\sf{\large 3 = {P}^{2}}$

$\dashrightarrow\sf{\large √3 = P}$

$☆\sf{\large Sinθ = \frac{p}{h} = \frac{ \sqrt{3} }{2} }$

$☆\sf{\large Tanθ = \frac{ \sqrt{3} }{1} = \sqrt{3} }$