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Answer:
Solving LHS=cos(60
o
−60
o
)=cos0
o
=1
Solving RHS=cos60
o
×cos60
o
+sin60
o
×sin60
o
=cos
2
60
o
+sin
2
60
o
(Putting the value A=B=60
o
)
we know that
cos60
o
=
2
1
;sin60
o
=
2
3
=(
2
1
)
2
+(
2
3
)
2
=
4
1
+
4
3
=
4
4
=1=RHS
Hence proved
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