Question

cosB=12/13 the value of sinB​

Answer 1

Heya,

Formula :-

${ \sin( \beta ) }^{2} + { \cos( \beta ) }^{2} = 1$

Given, cosB = 12/13

Putting in the formula

sin²B + 144/169 = 1

=> sin²B = 1 - 144/169

=>sin²B = 25/169

=> sinB = √25/169

=> sinB = 5/13.

Answer 2

Step-by-step explanation:

Dear friend use trignometric identity , trick etc .