Question

cose
1 + sin e
z
1-sine
cos e​

Answer 1

Answer:

$\frac{cose}{1 + sine} \\ on \: rationalization \\ = \frac{cose}{1 + sine} \times \frac{1 - sine}{1 - sine} \\ = \frac{cose(1 - sine)}{1 - {sin}^{2} e} \\ = \frac{cose(1 - sine)}{ {cos}^{2} e} \\ = \frac{1 - sine}{cose}$

hence proved

Answer 2

Answer:

this is correct.........................