Question

cose
3
sine
3)
+
1-tan e
= 1 + sin e
sin-cose​

Answer 1

Answer:

The prupose of this page is to prove the following formula: \sin 3x =4\sin x\sin(60^{\circ}-x)\sin(60^{\circ}+x). The easiest way to do that is to recourse to complex numbers and Euler's formula e^{i\theta}=\cos\theta +\sin\theta. ...