Question

cosec 0 + cot 0 = 1 -cos e
Solution:​

Answer 1

Step-by-step explanation:

$\cosec \theta + \cot \theta = \frac{ \sin \theta }{1 - \cos \theta}$

Taking L.H.S

$\cosec \theta + \cot \theta$

$\frac{1}{ \sin\theta} + \frac{ \cos \theta }{ \sin \theta}$

$\frac{1 + \cos\theta }{ \sin \theta}$

Multiple by 1 - cos0 N and D.

$\frac{1 + \cos\theta }{ \sin \theta} \times \frac{1 - \cos \theta }{1 - \cos\theta}$

$\frac{ 1 - { \cos }^{2}\theta }{ \sin \theta(1 - \cos\theta )}$

$● \: 1 - { \cos }^{2}\theta = { \sin }^{2} \theta$

$\frac{ { \sin }^{2}\theta }{ \sin \theta(1 - \cos\theta )} </p><p>$

$\frac{ { \sin }\theta \times \sin \theta }{ \sin \theta(1 - \cos\theta )} </p><p>$

$\frac{ { \sin }\theta }{ 1 - \cos\theta } </p><p>$

LHS = RHS