Question

cosec[1-cosA][cosesA+cotA]=1

Answer 1

HEY MATE HERE IS YOUR ANSWER ✍

LHS=1/sinA(1-cosA)*(1/sinA+cosA /sinA)

=(1/sinA-cosA/sinA)*(1+cosA)/sinA

=(1-cosA)/sinA*(1+cosA)/sinA

=1-(cos A*cosA)/(sinA*sinA)

=(sinA*sinA)/(sinA*sinA)

=1=RHS

HOPE THIS WORKS ❣❣