Question

Cosec=13/12,find the value of 2sin-3cos/4sin-9cos

Answer 1

Answer:

The answer is 3.

Step-by-step explanation:

Look:

since cosec=13/12

hence sin=12/13.

now, imagine a right angle triangle with base "x", perpendicular as 12 and hypo as 13 .                                                      

(make the Δ by keeping the base∠ as Ф )  

Using p.t,

x=5.

hence cos Ф=5/13.

now solve the sum:

(2*12/13-3*5/13) / (4*12/13-9*5/13)

={(24-15)/13} /{(48-45)/13}

=(9/13)/(3/13)

=9/13*13/3

=3.

:)

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