Question

cosec 17°30'/sec 72°30'

Answer 1

The value of $\dfrac{\csc 17°30'}{\sec 72°30'}$ is equal to one(1).

Step-by-step explanation:

We have,

$\dfrac{\csc 17°30'}{\sec 72°30'}$

To find, the value of $\dfrac{\csc 17°30'}{\sec 72°30'}$ = ?

∵ 17°30' + 72°30' = 90°

$\dfrac{\csc 17°30'}{\sec 72°30'}$

$=\dfrac{\csc 17°30'}{\sec(90-17°30')}$

Using the trigonometric identity,

$\csc A=\sec(90-A)$

$=\dfrac{\csc 17°30'}{\csc 17°30'}$

= 1

∴ The value of $\dfrac{\csc 17°30'}{\sec 72°30'}$ = 1

Thus, the value of $\dfrac{\csc 17°30'}{\sec 72°30'}$ is equal to one(1).

Answer 2

Answer:

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