Question

cosec^2 π÷2+cosec^2 2π÷5​

Answer 1

Answer:

Refer to the steps for solution.

Step-by-step explanation:

The given problem is $\frac{cosec^{2}2\pi }{2} +\frac{cosec^{2}2\pi }{5}$

We know that $cosecx=\frac{1}{sinx}$

Again we know that $sinn\pi =0$

Which means that every nth pi, the value of sin will be 0 given that the value of n is an integer

so in this case we are getting $cosec2\pi =\frac{1}{0}$ which is undefined thus the whole value remains undefined for this question